Python中的id()函数指的什么呢?

来源:网络时间:2018-01-25 13:01:02

  Python官方文档给出的解释是

Python中的id()函数指的什么呢?

  id(object)

  Return the “identity” of an object. This is an integer (or long integer) which is guaranteed to be unique and constant for this object during its lifeTIMe. Two objects with non-overlapping lifetimes may have the same id() value.

  CPython implementation detail: This is the address of the object in memory.

  由此可以看出:

  1、id(object)返回的是对象的“身份证号”,唯一且不变,但在不重合的生命周期里,可能会出现相同的id值。此处所说的对象应该特指复合类型的对象(如类、list等),对于字符串、整数等类型,变量的id是随值的改变而改变的。

  2、一个对象的id值在CPython解释器里就代表它在内存中的地址。(CPython解释器:)

?

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Stream Vera Sans Mono', 'Courier New', Courier, monospace !important; float: none !important; border-top-width: 0px !important; border-bottom-width: 0px !important; height: auto !important; color: rgb(0, 102, 153) !important; vertical-align: baseline !important; overflow: visible !important; top: auto !important; right: auto !important; font-weight: bold !important; left: auto !important; background-image: initial; background-attachment: initial; background-size: initial; background-origin: initial; background-clip: initial; background-position: initial; background-repeat: initial;" class="py keyword">class Obj():
 def __init__(self,arg):
  self.x=arg
if __name__ == '__main__':
 obj=Obj(1)
 print id(obj)  #32754432
 obj.x=2
 print id(obj)  #32754432
 s="abc"
 print id(s)   #140190448953184
 s="bcd"
 print id(s)   #32809848
 x=1
 print id(x)   #15760488
 x=2
 print id(x)   #15760464

  令外,用is判断两个对象是否相等时,依据就是这个id值

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class Obj():
 def __init__(self,arg):
  self.x=arg
 def __eq__(self,other):
  return self.x==other.x
if __name__ == '__main__':
 obj1=Obj(1)
 obj2=Obj(1)
 print obj1 is obj2 #False
 print obj1 == obj2 #True
 lst1=[1]
 lst2=[1]
 print lst1 is lst2 #False
 print lst1 == lst2 #True
 s1='abc'
 s2='abc'
 print s1 is s2  #True
 print s1 == s2  #True
 a=2
 b=1+1
 print a is #True
 a = 19998989890
 b = 19998989889 +1
 print a is #False

  is与==的区别就是,is是内存中的比较,而==是值的比较

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