python查找指定具有相同内容文件的方法

来源:网络时间:2018-02-26 10:10:19

  本文实例讲述了Python查找指定具有相同内容文件的方法。分享给大家供大家参考。

python查找指定具有相同内容文件的方法

  具体如下:  python代码用于查找指定具有相同内容的文件,可以同时指定多个目录  调用方式:python doublesdetector.py c:;d:;e: > doubles.txt  ?

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

18

19

20

21

22

23

24

25

26

27

28

29

30

31

32

33

34

35

36

37

38

39

40

41

42

43

44

45

46

47

48

49

50

51

52

53

54

55

56

57

58

59

60

61

62

63

64

65

66

67

68

69

70

71

72

73

74

75

76

77

78

79

80

81

82

83

84

85

# Hello, this script is written in Python -

# doublesdetector.py 1.0p

import os, os.path, string, sys, sha

message = """

doublesdetector.py 1.0p

This script will Search for files that are identical

(whatever their name/date/TIMe).

Syntax : python %s <directories>

where <directories> is a directory or a list of directories

separated by a semicolon (;)

Examples : python %s c:windows

python %s c:;d:;e: > doubles.txt

python %s c:program files > doubles.txt


This script is public domain. Feel free to reuse and tweak it.

The author of this script Sebastien SAUVAGE <sebsauvage at sebsauvage dot net>

""" % ((sys.argv[0], )*4)

def fileSHA ( filepath ) :

""" Compute SHA (Secure Hash Algorythm) of a file.

Input : filepath : full path and name of file (eg. 'c:windowsemm386.exe')

Output : string : contains the hexadecimal representation of the SHA of the file.

returns '0' if file could not be read (file not found, no read rights...)

"""

try:

file = open(filepath,'rb')

digest = sha.new()

data = file.read(65536)

while len(data) != 0:

digest.update(data)

data = file.read(65536)

file.close()

except:

return '0'

else:

return digest.hexdigest()

def detectDoubles( directories ):

fileslist = {}

# Group all files by size (in the fileslist dictionnary)

for directory in directories.split(';'):

directory = os.path.abspath(directory)

sys.stderr.write('Scanning directory '+directory+'...')

os.path.walk(directory,callback,fileslist)

sys.stderr.write('n')

sys.stderr.write('Comparing files...')

# Remove keys (filesize) in the dictionnary which have only 1 file

for (filesize,listoffiles) in fileslist.items():

if len(listoffiles) == 1:

del fileslist[filesize]

# Now compute SHA of files that have the same size,

# and group files by SHA (in the filessha dictionnary)

filessha = {}

while len(fileslist)>0:

(filesize,listoffiles) = fileslist.popitem()

for filepath in listoffiles:

sys.stderr.write('.')

sha = fileSHA(filepath)

if filessha.has_key(sha):

filessha[sha].append(filepath)

else:

filessha[sha] = [filepath]

if filessha.has_key('0'):

del filessha['0']


# Remove keys (sha) in the dictionnary which have only 1 file

for (sha,listoffiles) in filessha.items():

if len(listoffiles) == 1:

del filessha[sha]

sys.stderr.write('n')

return filessha

def callback(fileslist,directory,files):

sys.stderr.write('.')

for fileName in files:

filepath = os.path.join(directory,fileName)

if os.path.isfile(filepath):

filesize = os.stat(filepath)[6]

if fileslist.has_key(filesize):

fileslist[filesize].append(filepath)

else:

fileslist[filesize] = [filepath]

if len(sys.argv)>1 :

doubles = detectDoubles(" ".join(sys.argv[1:]))

print 'The following files are identical:'

print 'n'.join(["----n%s" % 'n'.join(doubles[filesha]) for filesha in doubles.keys()])

print '----'

else:

print message

  希望本文所述对大家的Python程序设计有所帮助。 

文章内容来源于网络,不代表本站立场,若侵犯到您的权益,可联系我们删除。(本站为非盈利性质网站) 联系邮箱:9145908@qq.com